Question

a block of mass 1 kg moves on a horizontal rough surface under the application of 10 Newton horizontal force if magnitude of frictional force acting on block is 2 Newtons calculate the work done by​

Answer 1

$\underline{ \mathfrak{\huge{\boxed{\fcolorbox{purple}{orange}{\purple{Answer\::-}}}}}} \\ \\ \star \rm \: \red{Given} \\ \\ \implies \rm \: mass \: of \: body = 1kg \\ \\ \implies \rm \: externel \: force \: on \: body = 10 \: N \\ \\ \implies \rm \: frictional \: force \: on \: body = 2 \: N \\ \\ \star \rm \: \red{To \: Find} \\ \\ \implies \rm \: work \: done \: by \: Frictional \: Force \\ \\ \star \rm \: \red{Formula} \\ \\ \implies \rm \: formula \: of \: work \: is \: given \: by \\ \\ \dagger \: \: \underline{ \boxed{ \bold{ \rm{ \pink{W = \vec{F} \: { \tiny{ \bullet}} \: \vec{d} = Fd \cos\theta}}}}} \: \: \dagger \\ \\ \implies \rm \: where \: \theta = angle \: between \: \vec{F} \: and \: \vec{d} \\ \\ \star \rm \: \red{Calculation} \\ \\ \implies \rm \:W = F{ \tiny{frictional}} \times d \times \cos180 \degree \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \orange{W = - 2d \: J}}}}}$