a block of mass 1 kg slides down on an inclined plane of inclination theta is equal to 30 degree find the work done by the weight of the blog as its size clothes 50 centimetre
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Work done by the block is 2.45J.
We know that,
Work done (W) = F × x × cos θ
where F is the Force,
x is the displacement
and θ is the angle between force and displacement.
We know, Force = Mass × Acc. due to gravity
Mass of the block = 1kg
Acc. due to gravity = 9.8 m/s²
So, force = (1 × 9.8)N = 9.8N
Also, displacement (x) = 50cm = 0.5m [1cm = 0.01m]
θ = (90° - 30°) = 60° [Angle in a right angled traingle = 90°]
Putting their respective values, we get:
W = 9.8 × 0.5 × cos 60°
= 2.45 N-m
= 2.45J [1 N-m = 1J]
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