A block of mass 1 kg travels down a smooth track. If the block starts slipping
on the track from a point Im above the horizontal surface. It will move a distance
5m on the rough horizontal surface and stop. Then friction coefficient of rough
surface is :
(A) 0.20
(B) 0.5
(D) 0.30
(C) 0.1
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Answer:
Let the velocity at point B be V.
By conservation of energy, mgh=
2
1
mv
2
⇒v=
2gh
.
Now deceleration due to friction is a=μg=0.2g.
So stopping distance, s=
2a
v
2
=2gh/0.4g=5h=5×1=5m
Explanation:
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