A block of mass, 10 kg, collides with a spring with a spring constant of 200 n/m at a speed of 12 m/s compressing the spring. when the block stops moving, how far is the spring compressed?
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this question answer is2.68 meters
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Answer:
Explanation:
delu+delk=0
1/2kx^2-1/2mv^2=0
12/root20 = x
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