Physics, asked by saket2194, 11 months ago

A block of mass 10 kg is acted upon by a force of
40 N parallel to the inclined plane as shown. Find
work done by applied force during first 10s of its
motion. Initially block was at rest.
40N
u=1/3
53°
(A) -4000J
(C) -8000J
(B) 4000J
(D) 8000J​

Answers

Answered by Anonymous
0

Explanation:

A block of mass 10 kg is acted upon by a force of

40 N parallel to the inclined plane as shown. Find

work done by applied force during first 10s of its

motion. Initially block was at rest.

40N

u=1/3

53°

(A) -4000J

(C) -8000J

(B) 4000J

(D) 8000J☑️☑️

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