A block of mass 10 kg is at rest on a rough
inclined surface of angle of inclination 30°. If
coefficient of friction between block and inclined
surface is 0.8, then the force applied by inclined
surface on block is (g = 10 m/s2)
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4
Answer:
uN = 10gsin30°
N = 10×10×1/2×0.8
=12.5 N
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