A block of mass 10 kg is kept on a horizontal
surface. A force Fis acted on the block as shown in
figure. For what minimum value of F, the block will
be lifted up?
TM 300
(a) 98 N
(c) 200N
(b) 49 N
(d) None of these
Answers
Answered by
5
Answer:
F = m * g
g= 9.8
10 * 9.8
98
force = 98 Newton
hope it will help you
Answered by
2
The correct option is 200 N
C ] 200 N
For the full solution refer to attachment
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