Question

A block of mass 10 kg is kept on inclined plane as shown in figure. A force F is applied on the block. The magnitude of force increases linearly from 20 N to 120 N. Draw the graph of friction V/s applied force F.
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Answer 1

Answer:

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Meenu drives her car for 3/2 hours with constant speed of 66 km /hr and then for another 45 minutes with a constant speed of 80 km/hr what was her average speed

Answer 2

Answer:

Explanation:

mgsin37  0  =10×10×3/5=60N

f1=μ=0.2mgcos37  

=0.2×10×10×4/5

=16N

Friction force alone is unable to balance mgsin37 0

. Hence, F is required for balancing. Here two cases arise.

Case I:  

If the block has tendency to slide down, friction on block will act upwards.

F + 16 = 60

RightarrowF=44N

This is the minimum force required for balancing.

Case II: If the block has on tendency to slide up, friction on block will act downwards.

F = 60 + 16⇒ F= 76 N

This is the maximum force required for balancing.

Therefore, for balancing 44N≤F≤16N