Question

A block of mass 10 kg is placed at a distance of 5m from the rear end of a long trolly as shown in fiugue

Answer 1

Mass of the block m = 15 kg. Coefficient of static friction µ = 0.18.

Acceleration of trolley α = 0.5 m/s^2.

According to the newton’s 2nd law of motion, the force f on the block created by motion of trolley is given by the specific relation F= ma = 15x 0.5 = 7.5 Newton.

Then, the force acted in direction of motion of trolley. F= µmg = 0.18x 15x10.