Question

A block of mass 10 kg is placed on a horizontal smooth surface five force each of 10 N applied to the block after every second when force is removed then the distance covered by block in 8 sec is​

Answer 1

ANSWER

Given,

Block of mass is 10kg

Rope of mass is 2kg

F=36N

So,

 At midpoint A of the rope

F=ma

36=(2+10)a

a=1236=3m/s2

Now,

36−TA=2m×a

36−TA=22×3

TA=36−3=33N

Where TA is the Tension at point A