Question

a block of mass 10 kg is placed on a rough horizontal surface of cofficient of friction 0.5 . The minimum force required to move the block is (g=10 m/s^2

Answer 1

Answer:

>50N

Explanation:

frictional force = normal force * frictional constant.

= 10*10 * 0.5

= 50N

But to move the block a greater force than friction in needed . So >50 N