A block of mass 10 kg is placed on a rough horizontal
surface having coefficient of friction = 0.5. If a
horizontal force of 100 N is acting on it, then
acceleration of the block will be
(a) 0.5 m/s2
(b) 5 m/s2
(c) 10 m/s2
(d) 15 m/s2
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Normal reaction = 100N
Friction force (F) = K * 0.5 = 0.5 * 100 = 50N
F = Ma
50 = 10 * a
a = 5 m/s2
a = 5 m/s2 is the direction of force
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