Physics, asked by BishalBarkakati, 1 year ago

a block of mass 10 kg is placed on an inclined a rough surface, what will be the acceleration by it?


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Answered by jashansidhubti
0
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Answered by Hiteshbehera74
0
f = μR
f = μmgcos∅

FBD of block,
mgsin∅-μmgcos∅ = ma
gsin∅-μgcis∅ = a
g(sin∅-μcos∅) = a

Therefore,
a = g(sin∅-μcos∅)m/s²
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