A block of mass 10 kg is released from the top of smooth wedge (whose inclination is at theta = 37)
which is moving with a constant velocity 10 m/s. The work done by the force applied by wedge on
the block in 2 sec will be (in joules) :-
(A) 960
(B) 1600
(C) Zero
(D) 720
Answers
Answered by
0
Answer:
The answer will be 0 hope it will help you
Similar questions