Question

A block of mass 10 kg is sliding on a surface
inclined at an angle of 30° with the horizontal. If the
coefficient of friction between the block and the
surface is 0.5, find the acceleration produced in the
block.
(Ans. 0.657 ms 3​

Answer 1

▶ Solution :

_________________________________

✴ GiveN :

▪ Mass of block = 10kg

▪ Angle of inclination = 30°

▪ Co-efficient of friction b/w the block and surface = 0.5

_________________________________

✴ To Find :

▪ Net acceleration of the block.

(First, see the attachment for better understanding)

_________________________________

✴ Concept :

▪ We can solve this question with the concept of Newton's second law of motion.

▪ As per this law,

☞ Fnet = mass × acceleration

_________________________________

✴ Calculation :

→ Fnet = mg sinΦ - umg cosΦ

→ ma = mg sinΦ - umg cosΦ

→ a = gsinΦ - ugcosΦ

→ a = g(sin30°) - 0.5g(cos30°)

→ a = 10×(1/2) - 5×(√3/2)

→ a = 5 - 2.5√3

→ a = 5 - 4.325

→ $\boxed{\bf{\red{a=0.675ms^{-2}}}}$

Answer 2

Answer:

* GiveN:

- Mass of block = 10kg

· Angle of inclination = 30°

Coefficient of friction b/w the block and surface = 0.5

* To Find :

Net acceleration of the block.

(First, see the attachment for better understanding)

*

Concept :

We can solve this question with the concept of Newton's second law of motion.

- As per this law,

Fnet = mass x acceleration

*

Calculation :

Fnet = mg sino - umg coso

ma = mg sino - umg cosO

a = sino - coso

a = g(sin30°) - 0.5g(cos30°)

= 10x(1/2) - 5×(V3/2)

= 5 - 2.5V3

- a

a = 5 - 4.325

a = 0.675ms -2