Question

A block of mass 10 kg is to be raised from the bottom to the top of a smooth incline of
inclination 30° and length 5m. Work done is 1)245 joule
2) 250 joule 3) 240 joule 4) 975

help me out me with this question please please ​

Answer 1

Given :

▪ Mass of block = 10kg

▪ Angle of inclination = 30°

▪ Distance covered by block = 5m

To Find :

▪ Work done to raise block from bottom to the top.

Concept :

✏ This question is completely based on the concept of work-energy theorem.

✏ As per WET,

☢ Work done = Change in energy

Calculation :

☞ If a body of mass m is raised through height h, then

→ W = mgh

→ W = mg(s × sinΦ)

→ W = 10×10×5×sin30°

→ W = 500/2

→ W = 250J (Option-2)

Answer 2

Answer:

answer 250J

Explanation:

this is based on work energy theorem.

W=mg sin tita

W=500/2

W=250J.