Question

A block of mass 10 kg moving on a rough horizontal table with an initial velocity of 4
m/s travels for 5 meters and stops. Assuming that the block decelerated uniformly, find
the friction force that acted on the block when the block was decelerating.

Answer 1

Explanation:

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Answer 2

Given: A block of mass 10 kg moving on a rough horizontal table with an initial velocity of 4 m/s travels for 5 meters and stops.

To find: Friction force that acted on the block

Explanation: Let mass of the block be m, its initial velocity be u, final velocity be v and distance covered during deceleration be s.

m= 10 kg

u= 4 m/s

v= 0 ( it stops after covering 5 m)

s= 5 m

Using kinematic equation:

=>${v}^{2} - {u}^{2} = 2as$

=>$0 - {4}^{2} = 2 \times a \times 5$

=>$- 16 = 10a$

=>$a = \frac{ - 16}{10}$

=>$a = \frac{ - 8}{5}$

=>a = -1.6 m/s^2

The value of acceleration is -1.6 m/s ^2.

Frictional force that acts on the body

= Mass of body* Acceleration

= 10 * -1.6 N

= -16 N

Therefore, the frictional force that acted on the block is -16 N.