Question

A block of mass 10 kg placed on rough horizontal surface having coefficient of friction 0.5,if a horizontal force of 100 N is acting on it then acceleration of the block will be(g=10 m/s2)

Answer 1

Given

Mass (M) = 10kg

Co-efficient of friction (K) = 0.5

Horizontal force = 100 N

g = 10m/s2

Solution

Normal reaction = M * g = 10 * 10

Normal reaction = 100N

Friction force (F) = K * 0.5 = 0.5 * 100 = 50N

F = Ma

50 = 10 * a

a = 5 m/s2

a = 5 m/s2 is the direction of force

Answer 2

I hope this helps you !