: A block of mass 100 kg is suspended as shown in the figure.
the tensions T, and T, in the two ropes. Take the value of g = 9.8 m/s?.
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Tcos45
o
=T
′
Tsin45
o
=Mg=100×10=100g
2
T
=100g⇒T=100
2
gN
T
′
=Tcos45
o
=100
2
g×
2
1
=100gN
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