A block of mass 100kg is set into motion on a friction less pulley and a rope system as shown in the figure . What horizontal force should be applied to produce in the block of an acceleration of 10 m/s^2.
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F=ma
force = mass ×accelaration
force= 100 ×10
force = 1000 N
mass =100kg
acceleration =10m/s^2
force = mass ×accelaration
force= 100 ×10
force = 1000 N
mass =100kg
acceleration =10m/s^2
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Answer:
1000000N
Explanation:
In this given diagram we have to consider the equilibrium of forces. We have the object at rest because no external forces are being applied to the box horizontally. And vertically the weight of the object which is mg is being cancelled as the same force is exerted on it due to equal and opposite force reaction. (Newton's 3rd law)
Now as we've a frictionless pulley when an external force is applied we will have no external forces applied on the object opposing the motion in play.
Therefore the force applied will be mass multiplied by acceleration which will be
Force = mass * acceleration
Mass is 100 kgs or 100000gms.
Acceleration 10m/s²
Force will be 1000000 Newtons
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