Physics, asked by jayapradha, 1 year ago

A block of mass 10kg is moving on a rough surface as shown in the figure. The frictional force acting on the block is

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Anonymous: whats the options dude ?
jayapradha: 1) 20N 2) 60N 3)40N 4) 80N
Anonymous: Nad whats the answer ?
jayapradha: 60N

Answers

Answered by Anonymous
105
Hii..

➡️ Answer is in attachment !

Hope this helps !
Attachments:
Answered by shirleywashington
64

Answer:

F = 60 N

Explanation:

It is given that,

Mass of block, m = 10 kg

Force, F = 20 N

Coefficient of friction, μ = 0.6

We have to find the frictional force acting on the block.

F=\mu N

Where N is normal force, N = mg

F=\mu mg

So, F=0.6\times 10\times 10

F=60\ N

Hence, the frictional force acting on the block is 60 N. The correct option is (2) " 60 N".

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