Question

a block of mass 10kg is placed on a horizontal surface connected by an cord passing over a friction less pulley to a hanging block of mass 10 kg. if the coefficient is 0.5​

Answer 1

Answer:

For mass A:T−μm

1g=m

1 a

→T=m

1a+μm

1g→(1)

For mass B:m

2g−T=m 2a

→T=m

2 g−m 2 a→(2)

From (1) and(2)

m1 a+μm1 g=m2 g−m 2a=m

1+m

2(m2 −μm1)g

a=10+10

(10−0.5×10)10

Thus a=2.5m/s 2

Explanation:

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Answer 2

Answer:

Thanks a lot

Explanation:

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