A block of mass 10kg is sliding on a surface inclined at an angle of 30°with the horizontal. if The coefficient of friction btween the block and the surface is 0.5 . Find the acceleration produced in the block
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F=ma
F=kmg
then ma=mg sin - kmg cos
a=10*1/2-0.5*10*1.732/2
a=5-4=3301
a=0.6699
F=kmg
then ma=mg sin - kmg cos
a=10*1/2-0.5*10*1.732/2
a=5-4=3301
a=0.6699
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