A block of mass 10kg is suspended at a distance of 20cm from the center of a uniform bar 1m long .what force is required to balance it at it ceneter of gravity by applying the force at the other end of the bar?
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Answer:
mass= 10 kg
distance=20cm which will be 0.2 m
f=?
f= mass / distance
f=10kg/0.2m
=00.2
Explanation:
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