Question

A block of mass 10kg on a rough horizontal surface. A horizontal force 4N is applied on it.if coefficient of static friction between those two sufaces os 0.5 frictional force between the two surface in contact is

Answer 1

4N as the force applied is less than maximum frictional force ( i.e. 10kg × 10m/s^2 × 0.5 = 50 N) .therefore frictional force is equal to the the force applied

Answer 2

Answer:

mass = 10kg

applied force= 4N

coefficient= 0.5

Explanation:

f = coefficient×m×g

0.5 ×4×10

20N

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