Question

A block of mass 10kg rests on a rough inclined plane at an angle of 40° to the horizontal. A force of 60N is applied parallel to the plane upwards. Calculate the acceleration with which the body moves if the coefficient of friction is 0.2​

Answer 1

m=10kg

let coefficient of friction be k and acceleration be a

let the body moves down

now,mgsin40-kmgcos40-60=ma

100×0.64-0.2×100×0.76-60=10a

64-15.2-60=10a

a= -1.12m/s^2

since,acceleration is -ve so body moves up with acceleration = 1.12 m/s^2