Question

A block of mass 120 g moves with a speed of 6.0 m/s on a frictionless horizontal surface towards ano
block of mass 180 g kept at rest. They collide and the first block stops. Find the speed of the other block
after the collision

Answer 1

Answer:

6.66m/s

Step-by-step explanation:

m1=120g. m2=180g

u1=6.0m/s. u2=0m/s

v1=0m/s. v2=x

according to law of conservation of momentum

m1u1+m2u2= m1v1+m2v2

120×6+180×0=120×0+180x

1200=180x

1200/180=×

6.66m/s=x