a block of mass 120g moves with a speed of 6.0m/s on a frictionless horizontal surface towards another block of mass 180kg kept at rest . They collide and the first block stops. Find the other block after the collision
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Given!
a block of mass 120g moves with a speed of 6.0m/s on a frictionless horizontal surface towards another block of mass 180kg kept at rest . They collide and the first block stops.
Data:
v1=velocity 1=6m/s
law of conservation of momentum
m1=120g
m2=180kg
180kg--->xg
180kg*1000=180000g
m2=180000g
m1*v1=m2*v2
120*6=180000*v2
0.004=v2
or v2=0.004 m/s
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