Question

a block of mass 1400kg is moving with a velocity of 15m/s.a resistance force of 250N and an acceleration force of 600N acts on it. find the distance traveled by the truck in 10sec​

Answer 1

Explanation:

Given : m=1000 kg u=10 m/s t=10 s

Applied force F=1000 N (forwards)

Retarding force f=500 N (backwards)

Acceleration of the car in forward direction a=

m

F−f

=

1000

1000−500

=0.5 m/s

2

Using v=u+at

∴ v=10+0.5×10=15 m/s

Answer 2

Answer:

Acceleration of the truck: a=

2800

1200−500

=

4

1

m/s

2

S=ut+

2

1

at

2

=15×10+

2

1

×

4

1

×100=162.5m.

Answered By

Explanation:

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