Question

A block of mass 1kg is at x = 10 m and moving towards negative x-axis with a speed 6 ms-¹. Another block of mass 2kg is at x = 12m and moving towards positive x-axis with a velcoity of 4 ms-¹. at same instant. The position of CM after 2s is
a) 12.1 m
b) 13.1 m
c) 12.67 m
d) 13.67 m​

Answer 1

Answer:

W=KE

f

−KE

i

W=KE

f

−

2

1

mv

2

F−dx=KE

f

−

2

1

×10×10

2

−0.1xdx=KE

f

−500

0.1∫

20

30

xdx=KE

f

−500

0.1[

2

x

2

]

20

30

=KE

f

−500

=

2

0.1

[(30)

2

−(20)

2

]=KE

f

−500

−25=KE

f

−500

KE

f

=475J