A block of mass 1kg is placed on a rough wedge which is fixed on an elevator
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as the block is placed perpendicularly to the rough wedge therefore
F=mgsin theta
theta = 30 (given)
m = 1 kg also given
then F = 1× 10× 1/2
F= 5N
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A block of mass 1 kg is placed on a rough wedge is fixed on elevator moving upward with constant velocity 2m/s. from Newton's 3rd law , action and reaction are of equal in magnitude and directed in opposite directions.
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