Physics, asked by ajjaynavin216, 4 months ago

A block of mass 1kg moves on a horizontal rough surface under the application of 10N

horizontal force. If magnitude of frictional force acting on block is 2N. Assume that block

starts from rest. Calculate the work done at the ends of 2 seconds by: (3)

(i) Gravity force

(ii) 10 N force

(iii) Frictional force.

Answers

Answered by Anonymous

☞

Assume no friction, the motion of the block will be in the direction of applied force. The friction opposes relative motion between two surfaces. The direction of friction will be opposite to relative motion, i.e., in leftward direction.

Now let us find the maximum friction force.

f max =f min μs N=0.2×1×10=2N

a. If F=1.0N

If the block is at rest friction acting on the block, f=F= 0.1N.

As f<f lim

hence, friction will be of static nature and acceleration of the block will be zero.

b. If F= 0.2 N

Here the applied force equals limiting friction. The block is on the verge of slipping.

or f=f lim =2.0N

c. If F=2.5N

Here the applied force is greater then the magnitude of the maximum nature of static friction. The nature of friction between the block and ground is of kinetic nature.

or f=f k=μ k

N=0.15×1×1.5N...

hope it will help you :)

Answered by hrishith

Answer:

i)0

ii)160J

iii)-32J

Explanation:

If there was no friction, the motion of the block will be in the direction of applied force. The friction opposes relative motion between two surfaces. The direction of friction will be opposite to relative motion, i.e., in leftward direction.