Question

a block of mass 2.0 kg is placed on a smooth horizontal surface.Two forces F1=20N and F2=N are acting on the body in directions making an angle of 30° and 60° to the surface .The reaction of the surface on the body is (a) 20N (b) 25N (c) 5N (d) zero

Answer 1

Answer:

(D) zero

Explanation:

here,

F1sin30+F2sin60=2g...............(1)

=20*1/2+N*√3/2=20

=N=20√3

putting the value of N in equ (1).

we get

Rexn=0

Answer 2

Answer:

0

Explanation:

The question is done by resolving the forces in the direction of the reaction force offered by the surface.

Hope it helps