Question

A block of mass 2.00 kg moving at a speed of 10.0 m/s accelerates at 3.00 m/s² for 5.00 s. Compute its final kinetic energy ?
Concept of Physics - 1 , HC VERMA , Chapter " Work and Energy"

Answer 1

Hello Dear.

Mass of the block (m) = 2 kg.
Initial speed of the block (u) = 10 m/s.
 Acceleration (a) = 3m/s² .
Time Taken (t) = 5 sec.

 Now applying the formula ,

$a = \frac{v-u}{t}$ 
3 = (v-10)/5
v= 15 + 10
v= 25 m/s.

Thus final speed of the block is 25 m/s.

Now, Using the formula :- 

Final K.E = 1/2 (mv²)
K.E = 1/2 (2 × 25²)
K.E = 625 J.


Hence the final Kinetic energy of Block is 625 J.



Hope it Helps

Answer 2

HEY!!

_______________________________

✴u = 10m/s

✴a = 3m/s^2

✴t = 5sec

✴v= u + at

✴v= 10+ 3 × 5 = 25m/sec

▶▶Kinetic energy = 1/2mv^2 = 1/2 × 2 × 25 ×25 = 625J