A block of mass 2.0kg slides on a rough surface At=0 its speed is 2.0m/s it stops covering a distance of 20 cm because of the friction exerted by the surface on it Find the work done
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Answer:
initial Kinetic energy , K
1
=
2
1
mv
1
2
=
2
1
×2×2=2 J
Final Kinetic energy , K
2
=0
Using work energy theorem we get
Work done by friction= Change in kinetic energy = K
2
−K
1
=−2 J
Explanation:
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