Question

A block of mass 2 kg hangs from the rim of a wheel of radius 0.5m. On releasing from rest the block falls through 5m height in 2 second. The moment of inertia of the wheel i

Answer 1

The moment of inertia will be 1.5 kgm^2

As,

S = vt + 1/2 at^2

As block falls 5 m height in 2 seconds after releasing from its rest position.

So,  

acceleration = a = 2.5 meter per second

As we know that,

a = g / 1 + I/m R^2

By substituting the values, we get

2.5 = 10 / 1 + I/ 2 x (0.5)^2

Hence,

I = 1.5 kg meter square