Question

A block of mass 2 kg is kept on a smooth surface at rest connected to a relaxed vertical spring of length 10 cm connected to ceiling as shown. Force constant of spring is 400 N/m. The block is now displaced to right along surface and released when the spring makes 37° with vertical. The acceleration of block when released is in m/s2 equal to

Answer 1

Answer:

Correct option is D)

Compression of the spring x=5cm=5×10

−2

m

Using conservation of energy:

Initial M.E= Final M.E

i.e Potential energy spring =Kinetic energy of block

⇒

2

1

kx

2

=

2

1

mv

2

Or kx

2

=mv

2

⇒800×25×10

−4

=2×v

2

⇒v=1 m/s