a block of mass 2 kg is kept on the floor . the coefficient of static friction is 2.5 N. what is the frictional force between block and floor
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R→ Normal reaction
f→ frictional force
Given,
μ = 2.5N; m=2kg; R=mg
f = μR
f = μ(mg)
f = (2.5)(2)(10)
f = 50N
f→ frictional force
Given,
μ = 2.5N; m=2kg; R=mg
f = μR
f = μ(mg)
f = (2.5)(2)(10)
f = 50N
hariharan108:
there is no option like that
ok
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