Question

A block of mass 2 kg is moving along x-axis
with velocity 2 m/s. A force of 4 N acts on the
block along y-axis for 2 s. Speed of the
particle after 2 s is
​

Answer 1

Explanation:

mass(m)=2kg

initial velocity(u)=2m/s

Force=4N

Force=change in momentum

time

4N=2×v - 2×2

2

4N=2v-4

2

4×2=2v-4

8=2v-4

8+4=2v

12=2v

12/2=v

v=6

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