Question

A block of mass 2 kg is placed on a horizontal floor. The coefficient of static friction is 0.4. Of a force of 5 n is applied on the block parallel to floor, the net force exerted by floor on the block is:

Answer 1

Explanation:

normal force:

N = mg = 2 × 10 = 20 N

max friction force = uN = 0.4 × 20 = 8 N

since applied force = 5 N

if, applied force <= max friction force

body will be at rest.

so, friction force = applied force = 5 N...