Question

a block of mass 2 kg is placed on a rough inclined plane as shown in the figure so that it touches the spring the block is allowed to move download the spring will be compared to a maximum of​

Answer 1

$\mathbb{\huge{\purple{Zia\: Dilliwali}}}$

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Answer-- 13 cm .

Solution ✌

The block keeps moving till its velocity becomes 0 again.

No KE, implies, total work done by all forces = 0

Work done by gravity + friction = Work done on spring

Now W (Normal)=0

mgsin@x-umgcos@x=0.5 kx^2

by putting

x=13 Cm