Question

a block of mass 2 kg is placed on a smooth horizontal surface two forces F1 = 20 N and F2 = 5 N start acting on the block in opposite directions as shown . if block gets displaced by 5 m in the direction of net force then work done by F2 is​

Answer 1

Answer:

Hope it helped you!

Explanation:

Answer 2

Answer:

-25 joule

Explanation:

We are given that a block of mass 2 kg is placed on a smooth horizontal surface .

Two forces  $F_1=20 N$ and $F_2=5 N$ start acting on the block in opposite direction.

Displacement =5 m

Net force =20-5=15 N in the direction of $F_1$

Because two forces are acting in opposite direction.

Work done by $F_2=F_2s cos 180^{\circ}=5\times 5(-1)=-25 joule$

Because $F_2$ and displacement are in opposite direction.

Hence, the work done by $F_2=-25 joule$