Question

A block of mass 2 kg is Placed on a smooth horizontal surface. Two forces F1= 20 N and F2= 5N start acting on the block in opposite direction. If block gets displaced by 5 m in the direction of net force then work done by F2 is

Answer 1

Answer:

-25

Explanation:

As formula is

F×Scos(angle)

=5×5cos180(because the block is placed on a smooth horizontal surface)

=25cos180

=25(-1)

=-25

Answer 2

Answer:

-25

Explanation:

work done by f2 =fscos theeta theeta=180 the block placed on a smooth horizontal surface andW=5*5*cos 180=5*5*-1= -25J