A block of mass 2 kg is placed on a smooth horizontal surface. Two forces F1, = 20 N and F2, = 5 N start
acting on the block in opposite directions as shown. If block gets displaced by 5 m in the direction of net
force then work done by F2, is
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Answer:
-25 Joule
Explanation:
Work= Force x displacement
as the force applied is in opp. direction to the displacement
Therefore, work done is -ve.
-5N x 5m
=-25 Joule
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