Question

a block of mass 2 kg is placed on an incline at an angle of 37° with the horizontal. The coefficient of friction between block and surface is 0.7 what is the force applied by incline plane on the block​

Answer 1

Answer:

F=1.118096 Newton

Explanation:

θ=37°

friction (f)=0.7

mass(m)=2kg

now,

We know that,

F=mfcosθ

=mfcoa37°

=2×0.7×0.79864(cos37°=0.79864)

= 2×7/10×79864/100000

=1118096/1000000

=1.118096 Newton , answer ❤️