Question

A block of mass 2 kg is placed on the corner of a rough horizontal plank of mass 10 kg as shown below. The combined system is sliding towards the rigid wall on the smooth horizontal surface with constant velocity of 2 ms–1 without any relative motion between the blocks. After some time, the plank hits the wall and sticks to it, 2 kg block starts sliding over 10 kg plank. If the surface of plank provides a constant retardation of 6 ms–2, then what is the minimum length of plank such that the block just reaches to other end of plank? [Neglect the size of block with respect to plank]

Answer 1

Answer:

I am sorry

how much you want to be answered

Answer 2

Answer:

1/3m

Explanation:

u=2    v=0     a=-6       s=?

we know that     2as=v^2- u^2

so,

      -12s = 0^2- 2^2

      -12s = -4

       s = -4/-12

        = 1/3