A block of mass 2 kg is placed on the floor. If force of 2.8 N is applied on the block parallel at angle of 30 degree from horizontal then the acceleration of block is (g=10m/s^2)
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hlo mate here is ur ans....
Friction is a self adjusting force.
the max. value of it here is μmg = 0.4x20= 8 N
But since the applied force is less than 8N. So, the friction adjusts its value and new value becomes 2.8N so that block remains in equllibrium.
hope this helps uh dear :)
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