A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. If force of 2.8N is applied on the block parallel to the floor, the force of friction between the block and the floor g=10m per second.
Answers
Answered by
1
we know that
force of friction = force×friction
=0.4×2.8
=1.12
force of friction = force×friction
=0.4×2.8
=1.12
doradoggy:
no the is 2.8
Similar questions