Physics, asked by doradoggy, 1 year ago

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. If force of 2.8N is applied on the block parallel to the floor, the force of friction between the block and the floor g=10m per second.

Answers

Answered by govind1698
1
we know that
force of friction = force×friction
=0.4×2.8
=1.12

doradoggy: no the is 2.8
doradoggy: ans is 2.8
govind1698: I think so mass is given 2 kg then we will have to multiplied it by mass
doradoggy: mmm
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