A block of mass 2 kg is placed over 5 kg mass as shown. If coefficient of friction between all the surface is 0.5, then find maximum value of force ‘F’ so that both the blocks move together.
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The maximum value of force F we have to apply, so that the blocks move together is 35N
Explanation:
Given: A block of mass 2 kg is placed over 5 kg mass as shown. Coefficient of friction between all the surface is 0.5.
Find: Maximum value of force ‘F’ so that both the blocks move together.
Solution:
At bottom surface friction coefficient is 0.5
F = μN
N = (2+5)g = 17*10 = 70N
F =μN = 0.5 * 70 = 35N
So the maximum value of force F we have to apply, so that the blocks move together is 35N.
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