. A block of mass 2 kg is pulled along circular and from position X to Y as shown in figure. The done by the horizontal force is pulling the ball from X to Y is
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Answer:
Work done by applied force on the block=F×s
=F×s
=40×2
=80J
Work done gravitational force on the object=mg×s
=mg(−s) (-ve sign as direction of displacement and force is opposite here)
=2×10×−2
=−40J
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Answer:
√3/2 FR
Explanation:
Work done= FD, where d is displacement in direction of F. = Work done=FRsin,60⁰= √3/2 FR
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